The j2 to j3 leg we add a zero resistor I will break down the circuit We will join the j1 to j2 series resistors Now combine J1 to J3 resistors in series : 670 + 0 = 670 Now combine j1 and j3 in parallel.1/R = 1/670 + 1/1000R = 401.2 Add what is left in series now we can get the current of the circuit : I o = 9V / 2400ΩI o = 3.75mA We can now figure out the voltage drops V 1000 = 1kΩ * 3.75mA = 3.75VV 401 = 401.2Ω * 3.75mA = 1.5VV 1000 = 1kΩ * 3.75mA = 3.75VSeries resistors have same current but different voltages j1 to J3 is made up of two resistors 670Ω and 1kΩ.V 401 = 401.2Ω * 3.75mA = 1.5VSo this voltage goes through both resistorsV 670 = 1.5V and V1000 = 1.5V I670 = 1.5V / 670Ω = 2.24mAI1000 = 1.5V / 1000 = 1.5mA Zero resistor has no voltage or current. It was a place holder.Resistors in parallel have same voltages but different currents The current from j1 to j2 I2000 = 1.5V/2000Ω = 0.75mAI1000 =1.5V / 1000Ω = 1.5mA Last redraw Final circuit