How to solve resistors in parallel and series? We start furthest from the power inputs. The orange box has the first two. They are in series. So we add themR34 = R3 + R4R34 = 1kΩ + 1kΩ = 2kΩ Now we move on to the next two The next orange box has the two resistors in parallel1/R234 = 1/R2 + 1/R341/R234 = 1/1kΩ + 1/2kΩ1/R234 = 1 + 1/2 = 3/2R234= 0.67kΩ The last two resistors are in seriesRTotal = R1 + R234RTotal = 1kΩ + 0.67kΩ = 1.67kΩ